taking a peek at the pyramid, is really just 4 triangles stemming from a common top and touching a squarish base at the edges.
so hmmm to get the surface area of the pyramid, we can simply get the area of all those four triangles and the square and sum them up.
[tex]\stackrel{\textit{\LARGE Areas}}{\stackrel{\textit{four triangles}}{4\left[\cfrac{1}{2}(\stackrel{b}{10})(\stackrel{h}{4}) \right]}~~ + ~~\stackrel{square}{(10)(10)}}\implies 80~~ + ~~100\implies 180~in^2[/tex]
