A spinner with a yellow, blue, red, and green section is shown. The arrow is pointing at the yellow section. The fair spinner shown is spun 2 times. The set of possible outcomes are: S = {RR, BB, YY, GG, RB, BR, RY, YR, RG, GR, BY, YB, BG, GB, YG, GY} The number of yellows in the outcome is summarized in the table on the right. A 2-column table has 3 rows. The first column is labeled Yellow with entries 0, 1, 2. The second column is labeled Frequency with entries 9, 6, 1. Using the data from the theoretical probability table, what is the probability of the spinner landing only once on yellow in two spins? 0.0625 0.5625 0.375 1

All the possible outcomes have the same probability, so, the probability that in two spins the spinner land only once in yellow is given by the quotient between the number of outcomes that have only one yellow and the total number of outcomes.

All the outcomes are:

{RR, BB, YY, GG, RB, BR, RY, YR, RG, GR, BY, YB, BG, GB, YG, GY}

16 in total.

The ones where the spinner lands only once on yellow are:

{RY, BY, YB, YG, GY, YR}

6 outcomes.

So the probability is:

P = 6/16 = 0.375

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