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A gas cylinder contains 5.0 kg of propane. How many propane molecules are in the cylinder? The Avogadro constant, L = 6.022 x 1023 mol^-1
A 6.8 × 10^22
B 7.2 x 10^22
C 6.8 × 10^25
D 7.2 x 10^25
[1 mark]​

Respuesta :

ItzmeDipayan

Answer:

Here's your answer.

M(C3H8) = 44 g/mol

n(C3H8) = 5000 (g)/44 (g/mol) = 113,6 mol

[tex] N = n \times N_{a} = 113,6 \times 6,02 \times {10}^{23} \\ \\ = 684,1 \times 10 ^{23} \sf{molecules} [/tex]

Hope it helps you from my side

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