Respuesta :
Answer:
1.11 g
Explanation:
From the answer you're given that HCl is the limiting reactant.
Mg + 2HCl -> MgCl2 + H2
40.0 g
First of all you want to know the moles of HCl you actually have:
40.0 g HCl x [tex]\frac{1 moles of HCl}{36.45 g/mol}[/tex] = 1.09739 moles of HCl.
Where 36.45 is the molar mass of H (1.008) + Cl (35.45).
Since the limiting reactant is HCl you'll have to discover how much H2 is produced from the limited quantity of reactant you have:
1.09739 moles of HCl x [tex]\frac{1 moles of H2}{2 moles of HCl}[/tex] = 0.54869 moles of H2 is produced
Now you have to simply convert the moles of H2 in grams:
0.54869 moles of H2 x 2.016 g/mol H2 = 1.106 g
Where 2.016 is the molar mass of H2.
