Respuesta :
A)
First ionization energy of Li:
Li(g) + 520 kJ/mol → Li⁺(g) + e⁻
B)
Electron affinity of Fluorine:
F(g) + e⁻ → F⁻(g) + 328 kJ/mol
First ionization energy of Li:
Li(g) + 520 kJ/mol → Li⁺(g) + e⁻
B)
Electron affinity of Fluorine:
F(g) + e⁻ → F⁻(g) + 328 kJ/mol
Answer:
Part A:
Li(g) --> Li^+(g)+e^-
Part B:
F(g) + e^- --> F^-(g)