Using the Fundamental Counting Theorem, it is found that Saul choose from 2340 possible passwords.
It is a theorem that states that if there are n things, each with [tex]n_1, n_2, \cdots, n_n[/tex] ways to be done, each thing independent of the other, the number of ways they can be done is:
[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]
In this problem:
Then, the number of different passwords is given by:
N = 26 x 10 x 9 = 2340
More can be learned about the Fundamental Counting Theorem at https://brainly.com/question/24314866