Respuesta :

luana
[tex]4x^2-12x-16=0\ \ \ | put\ 4\ in\ front\ of\ the\ bracket\\\\ 4(x^2-3x-4)=0\ \ \ | write\ -3x\ as\ x-4x\\\\ 4(x^2+x-4x-4)=0\\\\4(x-4)(x+1)=0\\\\ x=4\ or\ x=-1[/tex]
Find the factors of -16
(2x-8)(2x+2)=0
So the factors were -8 and 2
2x(-8)= -16x | 2x(2)= 4
-16x+4=-12x
And now find the x
2x-8=0 2x+2=0
2x=8 2x=-2
X=4 X=-1
so x is equal to 4 & -1




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