Respuesta :
Given ↓
- The inequality 3(x+2)-x<8
To Find ↓
- Which values of x make the inequality true
Calculations ↓
We can't determine right off the bat what values of x make this inequality true, so we should solve it first.
First, use the distributive property and distribute 3 :
3(x+2)-x<8
3x+6-x<8
Now subtract 6 on both sides :
3x-x<8-6
3x-x<2
now , subtract the x's :
2x<2
Divide by 2 on both sides :
x<1
So the values of x less than 1 make this inequality true.
Let's try -1 (-1 is less than 1)
Plug it in ↓
3(-1+2)-(-1)<8
3(1)+1<8
3+1<8
4<8
4 is less than 8.
Therefore, the values of x that make this inequality true are indeed less than 1.
hope helpful ~
Answer:
x < 1
Step-by-step explanation:
Expand the brackets: 3 * x = 3x and 3 * 2 = 6
Current inequality: 3x + 6 - x < 8
Collect like x terms: 3x - x = 2x
Current inequality: 2x + 6 < 8
Collect like integer terms: subract 6 from both sides
Current inequality: 2x < 2
Convert 2x to x: divide both sides by 2
Final answer = x < 1
Hope this helps :)
