Respuesta :
A 0.506 g sample of solid calcium hydroxide was dissolved in some water and then titrated with 28.85 mL of hydrochloric acid to neutralize, then the molarity of HCl is 0.471 M.
How do we calculate molarity?
Molarity will be calculated by using the below equation as:
M = n/V, where
V = volume of solvent
n is the moles of solute and it will be calculated by using the below equation:
n = W/M, where
W = given mass
M = molar mass
Given chemical reaction is:
Ca(OH)₂ + 2HCl → CaCl₂ + 2H₂O
Moles of Ca(OH)₂ = 0.506g / 74.093g/mol = 0.0068 mol
From the stoichiometry of the reaction:
0.0068 moles of Ca(OH)₂ = reacts with 2×0.0068 = 0.0136 moles of HCl
Given volume of HCl = 28.85mL = 0.02885 L
On putting values on the molarity equation, we get
M = 0.0136 / 0.02885 = 0.471 M
Hence required molarity of HCl is 0.471 M.
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