A box has 14 candies in it: 3 are butterscotch, 7 are peppermint, and 4 are taffy. (Each candy falls into only one of these categories.) Laura wants to select two candies to eat for dessert. The first candy will be selected at random, and then the second candy will be selected at random from the remaining candies. What is the probability that the two candies selected are taffy?

Respuesta :

The probability that the two candies selected by Laura from the box are taffy which has 14 candies in it: 3 are butterscotch, 7 are peppermint, and 4 are taffy is 0.230.

What is the conditional probability?

The conditional probability is the happening of an event, when the probability of occurring of other event is given.

A box has 14 candies in it: 3 are butterscotch, 7 are peppermint, and 4 are taffy. (Each candy falls into only one of these categories.)

Let A is the event of selecting taffy in first attempt. Thus, the probability of it is,

[tex]P(A)=\dfrac{4}{14}[/tex]

Now 13 candies remain, in which 3 taffy candies are present. Let B is the event of selecting taffy in again. Thus, the probability of it is,

[tex]P(B)=\dfrac{3}{13}[/tex]

The probability of happening both event is,

[tex]P(A\cap B)=\dfrac{4}{14}\times\dfrac{3}{13}\\P(A\cap B)=\dfrac{12}{182}[/tex]

The probability that the two candies selected by Laura from the box are taffy is,

[tex]P(B| A)=\dfrac{\dfrac{12}{182}}{\dfrac{4}{14}}\\P(B| A)=0.230[/tex]

Thus, the probability that the two candies selected by Laura from the box are taffy which has 14 candies in it: 3 are butterscotch, 7 are peppermint, and 4 are taffy is 0.230.

Learn more about probability here:

brainly.com/question/1210781

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