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A sample of iron having a mass of 93.3 g is heated to 65.58 oC and is placed in 75.0 g of water raising the temperature of the water from 16.95 o C to 22.24 o C. Find the specific heat capacity for this iron sample. (Specific Heat of Water (C) = 4.184 J/go C)

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Answer:

0.271J/g°C

Explanation:

mass of iron=93.3g

∆°C=65.58

mass of water=75g

C of water=4.184

∆°C=22.4-16.95=5.29°C

mc∆°C of iron = mc∆°C of water

93.3×C×5.29=75×4.184×5.29

C=75×4.185×5.29/93.3×65.58

C=0.271J/g°C

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