The molarity of sodium chloride solution containing 284 g of NaCl in 2.20 L os solution would be 2.21 mole/Liter
Recall that:
Molarity = mole/volume
Also, Mole = mass/molar mass
Thus:
Mole of 284 g NaCl = 284/58.44 = 4.86 moles
Volume of the solution = 2.20 L
Therefore, the molarity of the solution can be calculated as;
molarity = 4.86/2.20 = 2.21 mole/Liter
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