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If 10 moles of a gas are at a pressure of 3.6 atm and at a temperature of 27°C, what is the volume of the container that the gas is in.

Respuesta :

Answer:

68.4 liters

Explanation:

PV = nR T       R = gas constant = .082057  L atm / K-mole

                        n = 10      T = 27C = 300.15 K

3.6 V = 10 * .082057 * 300.15      solve for V = 68.4 liters

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