Answer:
Answer is D. [tex]\frac{121}{49}a^8b^2[/tex]
Step-by-step explanation:
We expand the powers.
[tex]\frac{11}{7}^2*(a^4)^2*(b)^2\\\frac{11}{7}*\frac{11}{7}*(a^4)(a^4)*(b*b)\\\frac{121}{49}*(a^8)*(b^2)[/tex]
when doing variable power you add them together.
a^4*a^4=a^(4+4) , b^1*b^1=b^(1+1)
