Respuesta :

janmilczek

Answer:

D. [tex]\frac{12x+20}{5y^3}[/tex]

Step-by-step explanation:

When multiplying 2 fractions, you multiply the numerators and denominators, so we have:

[tex](\frac{3x+5}{y^6})(\frac{4y^3}{5}) = \frac{(3x+5)\cdot 4y^3}{y^6\cdot 5} = \frac{(3x+5)\cdot 4}{y^3 \cdot 5} = \frac{12x + 20}{5y^3}[/tex]

Answer:

4th option

Step-by-step explanation:

[tex]\frac{3x+5}{y^6}[/tex] × [tex]\frac{4y^3}{5}[/tex] ( cancel y³ and [tex]y^{6}[/tex] on numerator/denominator by y³ )

= [tex]\frac{3x+5}{y^3}[/tex] × [tex]\frac{4}{5}[/tex]

= [tex]\frac{4(3x + 5)}{5y^3}[/tex]

= [tex]\frac{12x+20}{5y^3}[/tex]

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