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The percentage by mass of water in Na2CO3.10H2O from the calculation is  62.9%

What is percentage by mass?

The term percentage by mass refers to the amount of a particular moiety by mass in a molecule.

In this case, we know that the molar mass of Na2CO3.10H2O is 286 g/mol the molar mass of the 10 moles of water is 180 g/mol hence the percentage by mass of water in the compound is; 180 g/mol /286 g/mol  * 100/1 = 62.9%

Learn more about percentage by mass: https://brainly.com/question/16885872

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Answer:

63.0

Explanation:

got it wrong so it told me the answer