Answer:
c) [tex]x=\sqrt{133}[/tex]
d)[tex]x=\sqrt{235}[/tex]
Step-by-step explanation:
Pythagorean Theorem: [tex]a^2+b^2=c^2[/tex]
c) Solve for that side length and then solve for x
[tex]4^2+y^2=10^2\\y=\sqrt{133} \\(\sqrt{84} )^2+7^2=x^2\\x=\sqrt{133}[/tex]
d) Solve for that side length and then solve for x
[tex]5^2+y^2=10^2\\y=\sqrt{(16^2-5^2)} \\(\sqrt{231} )^2+7^2=x^2\\x=\sqrt{235}[/tex]
