A sample of oxygen was collected in a tube over water. in the tube, there is a mixture of oxygen gas and gaseous water (steam). the total pressure of the gas mixture is 760. torr. if the pressure of gaseous water is 23.8 torr, what is the pressure of the pure oxygen? 99.8 torr 736 torr 740. torr 783 torr

Respuesta :

The ideal gas law exhibits the relationship between the pressure and the volume of the gas. The pressure of the pure oxygen in the sample will be 736.2 torrs.

What is Dalton's law?

According to dalton's law, the sum of the partial pressure of the individual gases gives the total pressure exerted in the system. It is given as,

[tex]\rm P_{T} = P_{1} + P_{2} + P_{3} ........+P_{n}[/tex]

In the sample, the mixture of oxygen and gaseous water is present so, the pressure of oxygen is calculated as:

Given,

The total pressure of the mixture = 760 torr

The pressure of the gaseous water (steam) = 23.8 torr

Substituting values in the equation:

[tex]\begin{aligned} \rm 760 \; torr &= \rm P_{O_{2}} + 23.8 \; torr\\\\&= 760 - 23. 8\\\\&= 736.2 \;\rm torr\end{aligned}[/tex]

Therefore, the pressure of the pure oxygen in the mixture is 736.2 torr.

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Answer:

C

Explanation:

740. torr