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An ideal gas, initially at a volume of 0.777778 L and pressure of 9 kPa, undergoes isothermal expansion until its volume is 7 L and its pressure is 1 kPa. Calculate the work done by the gas during this process. Answer in units of J.

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okpalawalter8

For an ideal gas, initially at a volume of 0.777778 L,  the work done by the gas during this process is mathematically given as

w=15.380613

What is the work done by the gas during this process.?

Generally, the equation for the work done  is mathematically given as

W=p1v1invfvi

Therefore

v2=p1v1/p2

v2=9*1.0.77778/1

v2=7.00002

In conclusion

w=7.00002ln7/0.777778

w=15.380613

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