Respuesta :

[tex]~~~~(3x-4)^2 = 22\\\\\implies 3x-4 = \pm\sqrt{22}\\\\\implies 3x = 4 \pm\sqrt{22}\\\\\implies x = \dfrac{4\pm \sqrt{22}}3 \\\\\text{Hence,}~~ x = \dfrac{4+ \sqrt{22}}3~~ \text{and}~~ x = \dfrac{4-\sqrt{22}}3[/tex]