Answer:
The answer is B. [tex]\frac{2x+1}{x^{2}-7} ,x\neq \sqrt{7}[/tex]
Step-by-step explanation:
[tex]f(x)=2x+1\\g(x)=x^{2} -7[/tex]
Focusing on the denominator makes it equal to = 0
[tex]x^{2} -7=0\\x^{2} =7\\x=+\sqrt{7},-\sqrt{7}[/tex]
If the denominator equals zero then the equation ends up undefined. A number over zero, zero can not go divided into a number.
