Respuesta :
Using addition
x-y+1/2x+y=1+5
x+1/2x+0y=6
3/2x=6
[tex] \frac{3}{2}x=6 [/tex]
3x=12
x=4
Using the value of x
x-y=1
4-y=1
y=3
With x as 4 and y as 3, their product is 12
And can be written as (4,3)
x-y+1/2x+y=1+5
x+1/2x+0y=6
3/2x=6
[tex] \frac{3}{2}x=6 [/tex]
3x=12
x=4
Using the value of x
x-y=1
4-y=1
y=3
With x as 4 and y as 3, their product is 12
And can be written as (4,3)
add them equations to cacncel y
x-y=1
1/2x+y=5 +
3/2x+0y=6
3/2x=6
times 2/3 both sides
x=4
sub back
x-y=1
4-y=1
-y=-3
y=3
x=4
y=3
the orderd pair for the intersection would be (4,3)
(y)(x)=(3)(4)=12
x-y=1
1/2x+y=5 +
3/2x+0y=6
3/2x=6
times 2/3 both sides
x=4
sub back
x-y=1
4-y=1
-y=-3
y=3
x=4
y=3
the orderd pair for the intersection would be (4,3)
(y)(x)=(3)(4)=12