Respuesta :
If Sin 60 = √3 / 2
Then, Cos 60 = ?
Well, we know :
Sin^2x + Cos^2x = 1
Let X = 60°
That is,
Sin^2(60) + Cos^2(60) = 1
(√3 / 2)^2 + Cos^2(60) = 1
3 / 4 + Cos^2(60) = 1
Cos^2(60) = 1 - 3/4
Cos^2(60) = 4/4 - 3/4
Cos^2(60) = (4-3)/4
Cos^2(60) = 1/4
Cos(60) = √(1/4)
Cos(60) = √1 / √4
Cos(60) = 1 / 2
This's answer right to the your question.
Then, Cos 60 = ?
Well, we know :
Sin^2x + Cos^2x = 1
Let X = 60°
That is,
Sin^2(60) + Cos^2(60) = 1
(√3 / 2)^2 + Cos^2(60) = 1
3 / 4 + Cos^2(60) = 1
Cos^2(60) = 1 - 3/4
Cos^2(60) = 4/4 - 3/4
Cos^2(60) = (4-3)/4
Cos^2(60) = 1/4
Cos(60) = √(1/4)
Cos(60) = √1 / √4
Cos(60) = 1 / 2
This's answer right to the your question.
Answer: it can also be 30°; √3/2
Step-by-step explanation:
i just plugged cos30° into a math website and it gave me the answer. you can always plug it in into a scientific calculator.