Respuesta :
Considering the playground to be a square:
Perimeter = x + x + x + x
P = 4x
Area = x²
Px = 4x²
x² = Px/4
Area = Px/4
The fencing will be equal to the perimeter, with area 256 sq yd
256 = Px/4
P = 1024 / x
Perimeter = x + x + x + x
P = 4x
Area = x²
Px = 4x²
x² = Px/4
Area = Px/4
The fencing will be equal to the perimeter, with area 256 sq yd
256 = Px/4
P = 1024 / x
Answer:
Part 1 : The area in terms of side length = [tex]x^2[/tex]
Area of square in terms of perimeter P : [tex](\frac{P}{4})^2[/tex]
Part 2: A simple equation to find the least amount of fencing necessary for a playground with an area of 256 square yards : [tex]256 = (\frac{P}{4})^2[/tex]
Step-by-step explanation:
Part 1 : For any given perimeter P, the rectangle that encloses the greatest area is a square. . Write an equation for the area, A, in terms of the perimeter P, and the side length x.
Solution :
We are given that the rectangle that encloses the greatest area is a square.
Let the side of the square be x
Let perimeter be P
So, perimeter of square'P' = [tex]4\times side = 4\times x =4x[/tex]
So,[tex]P=4x[/tex]
Area of square : [tex](side)^2=x^2[/tex]
Thus the area in terms of side length = [tex]x^2[/tex]
Now to find area in terms of perimeter :
Since perimeter [tex]P=4x[/tex]
[tex]\Rightarrow x= \frac{P}{4}[/tex]
Now, Area of square : [tex](side)^2[/tex]
So,Area of square in terms of perimeter P : [tex](\frac{P}{4})^2[/tex]
Part 2: Use the equation from Part I to result to write a simple equation to find the least amount of fencing necessary for a playground with an area of 256 square yards.
Since we have the equation of area in terms of perimeter :
[tex]Area = (\frac{P}{4})^2[/tex]
Note: Perimeter tells the amount of fencing
[tex]256 = (\frac{P}{4})^2[/tex]
Thus a simple equation to find the least amount of fencing necessary for a playground with an area of 256 square yards : [tex]256 = (\frac{P}{4})^2[/tex]