Using the rules of logarithms, you can change it to
ln([tex]3^{3}[/tex]) + ln([tex]c^{3} [/tex]) =
ln(27[tex]c^{3}[/tex])
This is because when you have a factor in front of a logarithm, that turns into an exponent, and when you add logarithms, you multiply the factors inside of the logarithm.
So your final answer is D.
