Consider these equations:

2S (s) + 3O2 (g)→2SO3 (g), ΔH = −792 kJ
2S (s) + 2O2 (g)→2SO2 (g), ΔH = −594 kJ
2SO2 (g) + O2 (g)→2SO3 (g), ΔH =?

What is the missing ΔH?

a) −294 kJ
b) −198 kJ
c) +198 kJ
d) +294 kJ

The Hess law of constant heat summation is used to determine the heat absorbed or evolved in a reaction as a sum of the heat absorbed or evolved over a sequence of reactions.

Looking at the reactions as shown, the missing enthalpy can be obtained from the other two which will give us the value of −198 kJ.

Learn more about enthalpy: https://brainly.com/question/7827769

Consider these equations: 2S (s) + 3O2 (g)→2SO3 (g), ΔH = −792 kJ 2S (s) + 2O2 (g)→2SO2 (g), ΔH = −594 kJ 2SO2 (g) + O2 (g)→2SO3 (g), ΔH =? What is the missing ΔH? a) −294 kJ b) −198 kJ c) +198 kJ d) +294 kJ

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What is the Hess law?

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Consider these equations:

2S (s) + 3O2 (g)→2SO3 (g), ΔH = −792 kJ
2S (s) + 2O2 (g)→2SO2 (g), ΔH = −594 kJ
2SO2 (g) + O2 (g)→2SO3 (g), ΔH =?

What is the missing ΔH?

a) −294 kJ
b) −198 kJ
c) +198 kJ
d) +294 kJ