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Totsw6) 33 grams of Beryllium hydride, BeH2, are dissolved
in 6.0 Liters of solution.
M001 loi 0.
no
Answer?

Respuesta :

Eduard22sly

The molarity of the solution obtained by dissolving 33 g of Beryllium hydride, BeH₂, in 6.0 Liters of solution is 0.5 M

What is molarity?

Molarity is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

How to determine the mole of BeH₂

  • Mass of BeH₂ = 33 g
  • Molar mass of BeH₂ = 9 + (1×2) = 11 g/mol
  • Mole of BeH₂ =?

Mole = mass / molar mass

Mole of BeH₂ = 33 / 11

Mole of BeH₂ = 3 moles

How to determine the molarity

  • Mole of BeH₂ = 3 moles
  • Volume = 6 L
  • Molarity =?

Molarity = mole / Volume

Molarity = 3 / 6

Molarity = 0.5 M

Thus, the molarity of the solution is 0.5 M

Learn more about molarity:

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