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An arrow is shot vertically upward at a rate of 190 feet per second from ground level. Use the projectile formula
h
=
−
16
t
2
+
v
0
t
+
h
0
h
=
-
16
t
2
+
v
0
t
+
h
0
to determine when the height of the arrow will be 471 feet.

Respuesta :

raphealnwobi

The height of the arrow will be 471 feet at 8.35s and 3.53s

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

h represent the height of the arrow after t seconds.

h(t) = -16t² + v₀t + h₀

v₀ is the initial velocity = 190 ft/s, h₀ is the initial height = 0m, hence:

h(t) = -16t² + 190t

At 471 feet:

471 = -16t² + 190t

0 = -16t² + 190t - 471

t = 8.35 or 3.53

The height of the arrow will be 471 feet at 8.35s and 3.53s

Find out more on equation at: https://brainly.com/question/2972832

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