Please help me bro please

Answer:
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Step-by-step explanation:
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So,
[tex]{\longrightarrow \it\qquad { \ { (6n - 4) {}^{ \circ} = {(5n + 7)}^{ \circ} }}}[/tex]
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Removing the brackets,
[tex]{\longrightarrow \it\qquad { \ { 6n - 4{}^{ \circ} = {5n + 7 \: }^{ \circ} }}}[/tex]
[tex]{\longrightarrow \it\qquad { \ { 6n - 5n = { 7 \: }^{ \circ} +4{}^{ \circ} }}}[/tex]
[tex]{\longrightarrow \it\qquad { \pmb{ n = { 11 \: }^{ \circ} }}}[/tex]
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Therefore,
We will use the concept of Vertically Opposite angle here, i.e at the point of Intersection of two straight lines, the VOA (Vertically Opposite Angles) are equal
By using this property we will be having ;
[tex]{:\implies \quad \sf (6n-4)^{\circ}=(5n+7)^{\circ}}[/tex]
[tex]{:\implies \quad \sf 6n-5n=7+4}[/tex]
[tex]{:\implies \quad \bf \therefore \quad \underline{\underline{n=11}}}[/tex]
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