Answer:
see explanation
Step-by-step explanation:
the horizontal leg = 7 units
the vertical leg = 2
using Pythagoras' identity to find the distance d
d = [tex]\sqrt{7^2+2^2}[/tex] = [tex]\sqrt{49+4}[/tex] = [tex]\sqrt{53}[/tex] ≈ 7.3 ( to 1 dec. place )
