Respuesta :
The value of sin-1(1) is negative startfraction pi over 2 endfraction, startfraction -pi over 2 endfraction.
What is the value of sin (π/2)?
The value of sin (π/2) is equal to the number 1. The value of the sin-1(1) has to be find out.
Suppose the value of this function is x. Thus,
[tex]x=\sin^{-1}(1)[/tex]
Solve it further,
[tex]\sin(x)=(1)[/tex] ......1
The value of sin (π/2) and -sin (-π/2) is equal to 1 such that,
[tex]\sin\dfrac{\pi}{2}=-\sin\left(-\dfrac{\pi}{2}\right)=1[/tex]
Put this value in the equation 1,
[tex]\sin(x)=\sin\left(\dfrac{\pi}{2}\right)=-\sin\left(-\dfrac{\pi}{2}\right)[/tex]
Thus, the range will be,
[tex]\left(\dfrac{\pi}{2},-\dfrac{\pi}{2}\right)[/tex]
Thus, the value of sin-1(1) is negative startfraction pi over 2 endfraction, startfraction -pi over 2 endfraction.
Learn more about the sine values here;
https://brainly.com/question/10711389
