Water is pumped from a tank at constant rate, and no more water enters the tank. If the tank contains 22,917 L at 2:45 PM and 8,077 L at 5:25 PM the same day, how much water will the tank contain at 6:10 PM that day?

The conversion rate of a physical quantity is the method by which a unit of measurement is changed from one process to another by following a standard conversion rate and dimensional analysis.

From the information given:

The difference in the time from 5:25 PM to 2:45 PM is 2 hours:40 minutes
If we convert 2 hours:40 mins to minutes, we have = 160 minutes

The difference in the water in the tank within these two periods is:

= 22917 L - 8077 L

= 14840 L

In one minute, the amount of Liter is:

= 14840/160

= 92.75 Liter/minute

Similarly, between 6:10 pm and 5:25 pm, there are 45 minutes difference.

Therefore, the amount of water that the tank will contain at 6:10 PM that

day is;
= 45 minutes × 92.75 Liter/minute

= 4174 Liters

Learn more about conversion rate here:

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