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An ionized calcium atom has a charge of +2
elementary charges. If this ion is accelerated through
a potential difference of 2.0 x 103 volts, the ion's
change in kinetic energy will be

Respuesta :

onyebuchinnaji

The change in the kinetic energy of the calcium ion's is 6.4 x 10⁻¹⁶ J.

Change in Kinetic energy of calcium atom

The change in the kinetic energy of the ion's which accelerated through the given potential difference is calculated as follows;

ΔK.E = qV

where;

  • ΔK.E is the change in kinetic energy
  • q is the charge of the ion
  • V is the potential difference

Substitute the given parameters in the above equation and solve for change in kinetic energy.

ΔK.E = (2e)V

ΔK.E = (2 x 1.6 x 10⁻¹⁹) x (2.0 x 10³)

ΔK.E = 6.4 x 10⁻¹⁶ J

Thus, the change in the kinetic energy of the calcium ion's is 6.4 x 10⁻¹⁶ J.

Learn more about potential difference and kinetic energy here: https://brainly.com/question/18963960

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