Answer:
Explanation:
For example 1, there is no friction, so the acceleration in example 1 is:[tex]\sum F=F=100=ma \rightarrow a=\frac{100}{50}=2 ms^{-2}[/tex]
For example 2, there is a friction, so the acceleration in example 2 is:
[tex]\sum F=F-f=100-40 = 60 = ma\rightarrow a_{2}=\frac{60}{50}=1.2 ms^{-2}[/tex]
Here we can say that "according to Newton's 2nd Law, the box in example 2 has less acceleration than in the example 1". So, the claim is denied.
