Respuesta :

Nonportrit

Answer:

[tex]x=1,y=\frac{7}{2}[/tex]

Explanation:

Given the following question:

[tex]5x-2=3[/tex]
[tex]-5+4y=9[/tex]

To solve a system of equations we must start by solving the first equation for x, and then we substitute the value of x in in the second equation and then solve for y to find the value of both variables.


[tex]5x-2=3[/tex]
[tex]-5+4y=9[/tex]
[tex]-2+2=0[/tex]
[tex]3+2=5[/tex]
[tex]5x=5[/tex]
[tex]5x\div5=x[/tex]
[tex]5\div5=1[/tex]
[tex]x=1[/tex]

Substitute and solve the second equation:
[tex]x=1[/tex]
[tex]-5+4y=9[/tex]
[tex]-5+5=0[/tex]
[tex]9+5=14[/tex]
[tex]4y=14[/tex]
[tex]4y\div4=y[/tex]
[tex]\frac{14}{4} =\frac{7}{2}[/tex]
[tex]y=\frac{7}{2}[/tex]

Your answers are "x = 1, and y = 7/2."

Hope this helps.

charliethebest2002

Answer:

x=1 and y=7/2

Explanation:

To solve this problem, isolate the term of x from one side of the equation.

5x-2=3 and -5+4y=9

5x-2=3

First, add by 2 from both sides.

5x-2+2=3+2

Solve.

3+2=5

Rewrite the problem down.

5x=5

Divide by 5 from both sides.

5x/5=5/5

Solve.

5/5=1

x=1

-5+4y=9

First, add by 5 from both sides.

-5+4y+4=9+5

Solve.

9+5=14

4y=14

Divide by 4 from both sides.

4y/4=14/4

Solve.

14/2=7

4/2=2

Rewrite as a fraction.

y=7/2

Dividing is another option.

7/2=3.5

y=7/2

Therefore, the correct answer is x=1 and y=7/2.

I hope this helps you! Let me know if my answer is wrong or not.

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