Answer:
0.500 mole of Xe (g) occupies 11.2 L at STP.
General Formulas and Concepts:
Gas Laws
- STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
Stoichiometry
- Mole ratio
- Dimensional Analysis
Explanation:
Step 1: Define
Identify.
0.500 mole Xe (g)
Step 2: Convert
- [DA] Set up: [tex]\displaystyle 0.500 \ \text{mole Xe} \bigg( \frac{22.4 \ \text{L Xe}}{1 \ \text{mole Xe}} \bigg)[/tex]
- [DA] Evaluate: [tex]\displaystyle 0.500 \ \text{mole Xe} \bigg( \frac{22.4 \ \text{L Xe}}{1 \ \text{mole Xe}} \bigg) = 11.2 \ \text{L Xe}[/tex]
Topic: AP Chemistry
Unit: Stoichiometry
