Answer:
[tex]3x(x-4)[/tex]
Step-by-step explanation:
[tex]3x^2-12x[/tex] cannot be factorised in the form (x+b)(x-b) unless one of the b's is zero, so I wonder if the expression is incomplete?
To factorise [tex]3x^2-12x[/tex], take out the common factor [tex]3x[/tex]:
[tex]\implies3x(x-4)[/tex]
Therefore, x = 0 and x = 4
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[tex]3x^2-12x[/tex] factorised in the form (x+b)(x-b) would be [tex](3x+0)(x-4)[/tex]
but it is not usual to have a zero in a factorised form.
