Answer:
2 + √3
Step-by-step explanation:
Multiply the expression by [tex]\dfrac{\sqrt{3} +1}{\sqrt{3} +1}[/tex] :
[tex]\implies \dfrac{\sqrt{3} +1}{\sqrt{3} -1}\times\dfrac{\sqrt{3} +1}{\sqrt{3} +1}=\dfrac{(\sqrt{3} +1)^2}{3+\sqrt{3}-\sqrt{3}-1}=\dfrac{(\sqrt{3} +1)^2}{2}[/tex]
[tex]\implies \dfrac{(\sqrt{3} +1)^2}{2}=\dfrac{3+2\sqrt{3}+1 }{2}=\dfrac{4+2\sqrt{3} }{2}=2+\sqrt{3}[/tex]
