Respuesta :
Answer:
Perimeter of rectangle = 2L + 2W
2L + 2 * 36 = 148
2L = 148 - 72
2L = 76
L = 38 inches
Given :-
- Width of rectangle = 36 inches
- Perimeter of rectangle = 148 inches.
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To find:-
- Length of rectangle
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Solution:-
We know:-
[tex] \bigstar \boxed{ \rm Perimeter \: of \: rectangle = 2(length + width)}[/tex]
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So:-
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[tex] \dashrightarrow \sf 148 = 2(length + 36) \\ [/tex]
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[tex] \dashrightarrow \sf 148 = 2(length) + 2(36) \\ [/tex]
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[tex] \dashrightarrow \sf 148 = 2(length) + 2 \times 36 \\ [/tex]
[tex] \\ [/tex]
[tex] \dashrightarrow \sf 148 = 2(length) + 72 \\ [/tex]
[tex] \\ [/tex]
[tex] \dashrightarrow \sf 148 = 2length + 72 \\ [/tex]
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[tex] \dashrightarrow \sf 148 - 72= 2length \\ [/tex]
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[tex] \dashrightarrow \sf76= 2length \\ [/tex]
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[tex] \dashrightarrow \sf 2length = 76 \\ [/tex]
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[tex] \dashrightarrow \sf length = \dfrac{76}{2} \\ [/tex]
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[tex] \dashrightarrow \sf length = \cancel \dfrac{76}{2} \\ [/tex]
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[tex] \dashrightarrow \bf length = 38 \: inches[/tex]