Based on the various lapse rates, the temperature at 9,000 meters will be 30.53°C.
= Sea level temperature - Lapse rate x Difference in Depth from last lapse rate
= 35 - (6.85 / 1,000 x 2,100)
= 20.62°C
= 20.62 - (11 / 1,000 x (3,500 - 2,100))
= 20.62 - (11/1,000 x 1,400)
= 5.22° C
= Temperature at 3,500 meters - Normal lapse rate x Difference from last lapse rate
Normal lapse rate = 6.5 ° C / 1,000 meters
= 5.22 - ( 6.5 / 1,000 x (9,000 - 3,500))
= 5.22 - ( 6.5 x 5.5)
= -30.53° C
In conclusion, the temperature at 9,000m will be -30.53°C.
Find out more on lapse rate at https://brainly.com/question/1236934.