Respuesta :

Molar mass of LiBr

  • 7+80=87g/mol

[tex]\\ \sf\hookrightarrow No\:of\;moles=\dfrac{Given\:mass}{Molar\:mass}[/tex]

[tex]\\ \sf\hookrightarrow No\:of\:moles=\dfrac{66.1}{87}[/tex]

[tex]\\ \sf\hookrightarrow No\:of\:moles=0.75mol[/tex]