Identify the zeros of the quadratic function! Please help

Answer:
-2.79, -4.21
Step-by-step explanation:
The function seen in the graph is 0.5 (x + 3.5)² - 1.
Hence,
[tex]0.5(x+3.5)^{2} -1=0\\0.5(x+3.5)^{2} =1\\(x+3.5)^{2} = 0.5\\x+3.5 = \sqrt{0.5}\\or\\ x+3.5=-\sqrt{0.5} \\[/tex]
Finding the first answer,
[tex]x+3.5=\sqrt{0.5} \\x=\sqrt{0.5}-3.5\\x=-2.79 (3sf)[/tex]
Finding the second answer,
[tex]x+3.5=-\sqrt{0.5}\\x=-\sqrt{0.5} -3.5\\x=-4.21(3sf)[/tex]