Respuesta :

#1

[tex]\\ \tt\bull\rightarrowtail Ba^{2+}+NO_2\longrightarrow Ba(NO_2)_2[/tex]

#2

[tex]\\ \tt\bull\rightarrowtail Ba^{2+}+SiO_3^{2-}\longrightarrow BaSiO_3[/tex]

#3

[tex]\\ \tt\bull\rightarrowtail Ba^{2+}+HSO^{4-}\longrightarrow Ba_4HSO_2[/tex]

#4

[tex]\\ \tt\bull\rightarrowtail Ba^{2+}+PO_4^{3-}\longrightarrow Ba_3(PO_4)_2[/tex]