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I faced this difficult when I was solving some question from chemical kinetics.
Ps help me find y

if 1=(2/3)^y

Respuesta :

kqranyc
y = 0

Solution:

1 = (2/3)^y
(2/3)^y = 1
((2/3)^y) = log(1)
y = log(1)/log(2/3)
y = 0

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