Answer:
y= 67°
Step-by-step explanation:
Step1:
∠FGE=60° since EGF is an equilateral triangle.
and we have ∠FGH=96°
and ∠DGH=180° (straight line)
so ∠EGD=180-96-60= 24°
Step 2:
ABCD is a rhombus, so ∠ABC=∠ADC=102°
and we have ∠ADG=155°
so ∠GDC=360-155-102=103°
Step 3:
Let the point K is the intersection between (CD) and (EG)
∠DKG=180-∠GDC-∠EGD=180-103-24=53°
So ∠EKC=∠DKG=53° (alternate exterior angles)
Last step:
we have ∠FEG=60° ( angle in an equilateral triangle)
so y=180- ∠EKC- ∠FEG=180-53-60=67°
y=67°
