Respuesta :

Answer:

[tex] let \: a = \frac{6}{7} \: and \: x = \frac{3}{8} \\ - 2x + a = - 2 \times \frac{3}{8} + \frac{6}{7} \\ = - \frac{3}{4} + \frac{6}{7} \\ = \frac{ - 21 + 24}{28} \\ = \frac{3}{28} [/tex]