Plz help Find AD……..

Answer:
AD = 65
Step-by-step explanation:
Using right triangle ABE
Applying Pythagoras' identity
AB² + BE² = AE²
30² + BE² = 34²
900 + BE² = 1156 ( subtract 900 from both sides )
BE² = 256 ( take square root of both sides )
BE = [tex]\sqrt{256}[/tex] = 16
Note that CD = BE = 16
Using the right triangle ACD
Applying Pythagoras' identity
AD² = AC² + CD² = 63² + 16² = 3969 + 256 = 4225 ( take square root of both sides )
AD = [tex]\sqrt{4225}[/tex] = 65