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A cart is going around a circular loop, as shown in the figure. The cart moves with the smallest speed necessary to stay in contact with the loop to complete a circular path at point 1. What is the speed of the cart at point 2?

A cart is going around a circular loop as shown in the figure The cart moves with the smallest speed necessary to stay in contact with the loop to complete a ci class=

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kainejones40

ja die antwoord is baie eenvoudig

ogorwyne

The speed of this cart at point 2 is given as √5GR

What is speed?

This is the distance that is covered by an object over a defined or a specific amount of time.

g = gravitational speed

m = mass of cart

r = radius

at 1 speed = v1

centripetal force = f1

f1 = mv1²/R

m1 = mg

mv1²/R = mg

cross multiply

v1² = gr

v1 = √gr

H = 2R

mgH + mv1²/2 = mv2²/2

2GH + v1² = v2²

2g(2R) + (√gR)² = v2²

4gr + GR = V2²

5GR = v2²

√5GR = v2

Therefore at point 2, the speed of the cart is given as √5GR

Read more on speed here: https://brainly.com/question/4931057

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