This is based on my assumption that white is the recessive trait.
1) find recessive allele frequency
[tex]q^{2}=\frac{23}{142}\\\\q^{2}=0.161971831\\\\\sqrt{q^{2}}=\sqrt{0.161...}\\\\ q=0.4024572412[/tex]
2) find dominant allele frequency
[tex]p+q=1\\\\p=1-q\\\\p=1-0.402...\\\\p=0.5975427588[/tex]
3) find heterozygous genotypic frequency
[tex]2pq=2(0.597...)(0.0402...)\\\\2pq=0.4809708204[/tex]
4) solve
[tex]heterozygous=(142)(0.480...)[/tex]
heterozygous = 68.2978565
In a population of 142, around 68 of the geese would be heterozygous.