Respuesta :

[tex]\huge\boxed{\bf{Process:}}[/tex]

[tex]{\boxed {\bold {8 abx - 8 ab ; 4 a^{2}x - 4 a^{2} ; 6 ax^{2} - 6 ax =}}}}}[/tex]

[tex]{\boxed {\bold {8abx-8ab=8ab(x-1)}}}}}[/tex]

[tex]{\boxed {\bold {4a^{2}x-4a^{2}=4a^{2}(x-1)}}}}}[/tex]

[tex]{\boxed {\bold {6ax^{2}-6ax=6ax(x-1)}}}}}[/tex]

♣• Now in here we simplify or do the Least Common Multiple, (LCM).

[tex]\frak{\pmb{\underline\green{8|2}}}[/tex]        [tex]\frak{\pmb{\underline\green{4|2}}}[/tex]        [tex]\frak{\pmb{\underline\green{6|2}}}[/tex]

[tex]\frak{\pmb{\underline\green{4|2}}}[/tex]        [tex]\frak{\pmb{\underline\green{2|2}}}[/tex]        [tex]\frak{\pmb{\underline\green{3|3}}}[/tex]

[tex]\frak{\pmb{\underline\green{2|2}}}[/tex]        [tex]\frak{\pmb{\underline\green{1|}}}[/tex]          [tex]\frak{\pmb{\underline\green{1|}}}[/tex]  

[tex]\frak{\pmb{\underline\green{1|}}}[/tex]  

♣• So the result of all this would be:

[tex]\huge\boxed{\bf{2a\:(x-1)}}[/tex] ✅

➥ I hope I have helped you, greetings!

Atte: ✦TheGirlSad✦

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